Re: What is the correct set of triples for this case?

Hi Micah,

Ok...I see your problem. Or rather mine, because I've assumed that the
RDF side of this is more obvious than it actually is. Sorry....

When triples are generated, the order doesn't matter. So as long as an
RDFa parser generates the three triples we're discussing, then it is
potentially conformant.

So when I said "exactly the same triples would be generated", I wasn't
meaning, "and in the same order"; they could be generated in any
order, as you have rightly pointed out, but no matter what happens,
you will get those three triples.

Regards,

Mark


On 13/03/2008, Micah Dubinko <mdubinko@yahoo-inc.com> wrote:
>
>  Mark, thanks for bearing with me. Your patience is commendable. :-)
>
>
>
>  >  Now, if the order of the inner elements was swapped, it would be different, right?
>  >
>
> >    1  <e rel="rel:foo">
>  >    2    <g about="http://x"/>
>  >    3    <f property="prop:bar" content="x"/>
>  >    4  </e>
>
> >
>  >  Would yield
>  >
>  >  <> rel:foo <http://x>
>  >  <http://x> prop:bar "x"
>  >
>  >  Right?
>
>  >No...exactly the same triples would be generated.
>
> > [  <> rel:foo _:a .
>
> >    _:a prop:bar "x" .
>  >    <> rel:foo<http://x> .
>
> > ]
>
>
>  OK, but I still think the first generated triple would be
>  <> rel:foo <http://x>
>
>  Tell me where I go off track. I added line numbers above.
>
>  1. Generates an incomplete forward triple with subject=<> and pred=rel:foo
>  2. Establishes a new subject, and thus completes the hanging triple
>  ergo <> rel:foo <http://x>
>  Right? Or wrong?
>
>  Thanks -m
>
>
>


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Received on Thursday, 13 March 2008 14:17:56 UTC