- From: Marko Smiljanic <m.smiljanic@utwente.nl>
- Date: Wed, 15 Oct 2003 19:05:09 +0200
- To: <xmlschema-dev@w3.org>
Hi, This is a question concerned with the property of "validation equality" between the schemas using "substitutionGroup"s and schemas using a "choice" compositor as a replacement for a substitutionGroup. The term "validation equality" between different schemas means that the sets of XML documents that can be validated by those different schemas are equal. Now, a short intro and then a question. *** The Short Intro (written in XSD-like language)... Lets have Schema 1 defined as: element A (abstract=true) element B (substitutionGroup="A") element C (substitutionGroup="A") element D () - sequence - element (ref="A") Now I convert Schema 1 to a "validation equal" Schema 2, presented below: element B () element C () element D () - sequence - choice -- element (ref="B") \_ element (ref="C") What I did is, replaced a reference to an abstract element "A" with a choice compositor, and then nest all the possible substitutions for "A" within this choice. I also removed element A as it is defined as abstract, otherwise, I would add it under the choice too. *** The question Do you think/know that it is possible to transform every XML schema having substitutionGroups using the "choice" trick above, and get the "validation equal" schema? Thanks, Marko Smiljanic ps. FYI I'm defining a graph-like model for XML schema needed in my research. The trick above would be a nice workaround to represent substitution groups in the model using "choice" that is already supported by the model. ************************* Research assistant, Database Technology Department of Computer Science, University of Twente P.O. Box 217, 7500 AE Enschede, The Netherlands Phone +31 (053) 489 4520, Fax ~ 2927 E-mail: m.smiljanic@utwente.nl WWW: www.cs.utwente.nl/~markosm
Received on Wednesday, 15 October 2003 13:06:48 UTC