- From: Dean Hiller <dhiller@avaya.com>
- Date: Wed, 15 Oct 2003 07:19:01 -0600
- To: xmlschema-dev@w3.org
If I have some xml implementating schema A.xsd <superclass> <someElement/> </superclass> And then I write B.xsd which extends A.xsd and the xml looks something like this <subclass xmnls="......A.xsd"> <someElement/> <anAddedElement/> </subclass> BUT, I must be missing something. There is now a program A which only knows about A.xsd. It should be able to receive the xml that adheres to B.xsd and just skip the unknown elements and only deal with the known ones(ie someElement). The problem is there seems to be nothing to tell the parser that subclass extends superclass unless you know of B.xsd. I thought the idea of extensions was object-orientedness. The subclass should be able to be read by program A as the superclass. (ie. program A knows about a car, and we created a Ford car, so program A can still see it as a car). I am afraid that a parser will puke at this since it does not adhere to A.xsd. There must be something else in the xml I am missing????? Also, how would I write the xsd and xml for this? I wish the tutorial explained more in this area. I would say this is by far the most important part of xsd's. Extension without breaking previous programs. Previous programs just ignore additional data. thanks, dean
Received on Wednesday, 15 October 2003 09:47:59 UTC