- From: Andy Seaborne <andy.seaborne@epimorphics.com>
- Date: Fri, 12 Aug 2011 17:55:59 +0100
- To: semantic-web@w3.org
On 12/08/11 17:36, Jitao Yang wrote:
> Dear all,
>
> suppose we have DATA:
>
> @prefix foaf: <http://xmlns.com/foaf/0.1/> .
>
> _:a foaf:name "Johnny Lee Outlaw" .
> _:a foaf:mbox <mailto:jlow@example.com <mailto:jlow@example.com>> .
> _:b foaf:name "Peter Goodguy" .
> _:b foaf:mbox <mailto:peter@example.org <mailto:peter@example.org>> .
> _:c foaf:mbox <mailto:carol@example.org <mailto:carol@example.org>> .
>
>
> can we write a SPARQL query like:
>
> PREFIX foaf: <http://xmlns.com/foaf/0.1/>
> SELECT *?property*
>
> WHERE{
> ?x foaf:*?property* "Peter Goodguy".
> }
>
> if we can not, can we write an equivalent SPARQL query? Namely, can we
> decompose schema and Class(or Property) in SPARQL query?
>
> Thanks,
> Jitao
SPARQL 1.1:
PREFIX foaf: <http://xmlns.com/foaf/0.1/>
SELECT ( substr( str(?p), strlen(str(foaf:))+1 )
AS ?property)
WHERE{
?x ?p "Peter Goodguy".
}
In SPARQL 1.0, you can't return anything not already in the graph : in
SPARQL 1.1 you can do some manipulation of RDF terms.
Because SUBSTR is fn:substring, indexes are 1-based.
Andy
Received on Friday, 12 August 2011 16:56:29 UTC