- From: Mischa Tuffield <mischa.tuffield@garlik.com>
- Date: Fri, 12 Aug 2011 18:20:23 +0100
- To: Andy Seaborne <andy.seaborne@epimorphics.com>
- Cc: "semantic-web@w3.org" <semantic-web@w3.org>
Excuse the top-post.
You can brutal about it in SPARQL 1.0 and use filter regex. Something like :
. FILTER ( regex( str(?p), "/http:\/\/xmlns\.com\/foaf/") )
It is kinda nasty, but will do the trick!
Mischa
Sent on the move
On Aug 12, 2011, at 5:55 PM, Andy Seaborne <andy.seaborne@epimorphics.com> wrote:
>
>
> On 12/08/11 17:36, Jitao Yang wrote:
>> Dear all,
>>
>> suppose we have DATA:
>>
>> @prefix foaf: <http://xmlns.com/foaf/0.1/> .
>>
>> _:a foaf:name "Johnny Lee Outlaw" .
>> _:a foaf:mbox <mailto:jlow@example.com <mailto:jlow@example.com>> .
>> _:b foaf:name "Peter Goodguy" .
>> _:b foaf:mbox <mailto:peter@example.org <mailto:peter@example.org>> .
>> _:c foaf:mbox <mailto:carol@example.org <mailto:carol@example.org>> .
>>
>>
>> can we write a SPARQL query like:
>>
>> PREFIX foaf: <http://xmlns.com/foaf/0.1/>
>> SELECT *?property*
>>
>> WHERE{
>> ?x foaf:*?property* "Peter Goodguy".
>> }
>>
>> if we can not, can we write an equivalent SPARQL query? Namely, can we
>> decompose schema and Class(or Property) in SPARQL query?
>>
>> Thanks,
>> Jitao
>
> SPARQL 1.1:
>
> PREFIX foaf: <http://xmlns.com/foaf/0.1/>
> SELECT ( substr( str(?p), strlen(str(foaf:))+1 )
> AS ?property)
>
> WHERE{
> ?x ?p "Peter Goodguy".
> }
>
>
>
> In SPARQL 1.0, you can't return anything not already in the graph : in SPARQL 1.1 you can do some manipulation of RDF terms.
>
> Because SUBSTR is fn:substring, indexes are 1-based.
>
> Andy
>
Received on Friday, 12 August 2011 17:22:14 UTC