- From: Henry S. Thompson <ht@cogsci.ed.ac.uk>
- Date: 09 Mar 2001 09:10:00 +0000
- To: Chetan Chudasama <cchetan@nms.fnc.fujitsu.com>
- Cc: xmlschema-dev@w3.org
Chetan Chudasama <cchetan@nms.fnc.fujitsu.com> writes:
> Hi,
>
> I am learning schemas and wanted to know how to extend
> attributes.
> By this I mean that if I define an attribute, a global
> attribute say "range" defined in one namespace
>
> <xsd:schema xmlns = "http://my.com/schemas/MySchema"
> targetNamespace = "http://my.com/schemas/MySchema"
> xmlns:xsd = "http://www.w3.org/2000/10/XMLSchema"
> version = ""
> elementFormDefault = "unqualified"
> attributeFormDefault = "unqualified">
> <xsd:attribute name = "range" use="default" value="5">
> <xsd:simpleType>
> <xsd:restriction base = "xsd:integer">
> <xsd:maxInclusive value = "5"/>
> <xsd:minInclusive value = "2"/>
> </xsd:restriction>
> </xsd:simpleType>
> </xsd:attribute>
> </xsd:schema>
>
>
> Now I define another schema in another namespace and I want
> to extend the attribute from this schema
> to increase the range keeping the default same. I know this
> can be done just by defining another attribute
> with a similar definition. But I would still like to know if
> that is possible and how?
Nope -- all simple type derivation is by restriction, and even in the
case of complex types, you can't add back something once you've taken
it away.
ht
--
Henry S. Thompson, HCRC Language Technology Group, University of Edinburgh
W3C Fellow 1999--2001, part-time member of W3C Team
2 Buccleuch Place, Edinburgh EH8 9LW, SCOTLAND -- (44) 131 650-4440
Fax: (44) 131 650-4587, e-mail: ht@cogsci.ed.ac.uk
URL: http://www.ltg.ed.ac.uk/~ht/
Received on Friday, 9 March 2001 04:10:24 UTC