Re: Decision from the Semantics TF: liberal baseline

But there isn't RDF/RDFS semantics.  There is RDF semantics and RDFS 
semantics.  (And datatype semantics but I don't think that that matters much 
here.)  What goes where?

peter


On 1/8/25 11:56 AM, Franconi Enrico wrote:
> 
> 
>> On 8 Jan 2025, at 17:55, Peter F. Patel-Schneider <pfpschneider@gmail.com> wrote:
>>
>> Complete?  For what?  What happened to the simple semantics?
> 
> I mean wrt the part on metamodelling in RDF/RDFS.
> —e.
> 
>>
>> peter
>>
>>
>> On 1/8/25 11:45 AM, Franconi Enrico wrote:
>>> This is my complete proposal:
>>>   * ⏩ |<r, [I+A](rdfs:Proposition)> ∈ IEXT([I+A](rdf:type))|
>>>                if |r ∈ range(RE)| or
>>>                if |∃ x,y . RE(x,[I+A](rdf:reifies),r)=y| ⏪️
>>>   * ⏩ |<r, [I+A](rdfs:Resource)> ∈ IEXT([I+A](rdf:type))|
>>>                if |r ∈ range(RE)| or
>>>                if |∃ x,y,z . RE(x,z,r)=y| or
>>>                if |∃ x,y,z . RE(r,z,x)=y| ⏪️
>>>   * ⏩ |<r, [I+A](rdfs:Property)> ∈ IEXT([I+A](rdf:type))|
>>>                if |∃ x,y,z . RE(x,r,z)=y| ⏪️
>>>  if the triple structure appears in S  then S RDF entails
>>> */reif1/*  sss aaa <<(xxx yyy zzz)>>  <<(xxx yyy zzz)>> rdf:type rdfs:Proposition .
>>> <<(xxx yyy zzz)>> rdf:type rdfs:Resource .
>>> sss rdf:type rdfs:Resource .
>>> aaa rdf:type rdfs:Property .
>>> */reif2/*  <<(xxx yyy zzz)>> aaa ooo  <<(xxx yyy zzz)>> rdf:type rdfs:Proposition .
>>> <<(xxx yyy zzz)>> rdf:type rdfs:Resource .
>>> ooo rdf:type rdfs:Resource .
>>> aaa rdf:type rdfs:Property .
>>> */reif3/*  sss rdf:reifies ooo  ooo rdf:type rdfs:Proposition .
>>>         —e.
>>>> On 8 Jan 2025, at 17:35, Franconi Enrico <franconi@inf.unibz.it> wrote:
>>>>
>>>> Option 1 (the current option) adds metamodelling inference only for asserted triples.:
>>>>
>>>>
>>>>         Option 1 (shallow metamodelling)
>>>>
>>>>
>>>>           * ⏩ |<[I+A](r), [I+A](rdf:Proposition)> ∈ IEXT([I+A](rdf:type))|
>>>>                       if |r is a triple term and ∃ x,y . (<x,[I+A](r)> ∈
>>>>             IEXT(y)) ⋁ (<[I+A](r),x> ∈ IEXT(y))|
>>>>                       or if |∃ x . <x,[I+A](r)> ∈ IEXT([I+A](rdf:reifies))| ⏪️
>>>>
>>>> Note that this is just wrong since in this case we have
>>>> [I+A](rdfs:Resource) ≠ IR
>>>> [I+A](rdfs:Property) ≠ IP
>>>>
>>>>
>>>>         Option 2 (true metamodelling)
>>>>
>>>>
>>>>           * ⏩ |<r, [I+A](rdf:Proposition)> ∈ IEXT([I+A](rdf:type))|
>>>>                       if |r ∈ range(RE)| or
>>>>                       if |∃ x,y . RE(x,[I+A](rdf:reifies),r)=y| ⏪️
>>>>           * ⏩ |<r, [I+A](rdfs:Resource)> ∈ IEXT([I+A](rdf:type))|
>>>>                       if |r ∈ range(RE)| or
>>>>                       if |∃ x,y,z . RE(x,z,r)=y| or
>>>>                       if |∃ x,y,z . RE(r,z,x)=y| ⏪️
>>>>           * ⏩ |<r, [I+A](rdfs:Property)> ∈ IEXT([I+A](rdf:type))|
>>>>                       if |∃ x,y,z . RE(x,r,z)=y| ⏪️
>>>>
>>>>
>>>> Option 2 adds new metamodelling conditions, which implies that
>>>>
>>>> [I+A](rdfs:Resource) = IR
>>>>
>>>> [I+A](rdfs:Property) = IP
>>>>
>>>> as it should.
>>>> The entailment pattern for option 2 will have "if the triple structure appears in S”.
>>>>
>>>> —e.
>>>>
>>>>> On 8 Jan 2025, at 17:17, Doerthe Arndt <doerthe.arndt@tu-dresden.de> wrote:
>>>>>
>>>>> Dear Niklas,
>>>>>
>>>>>>
>>>>>> I think that it should be derived. And I agree that the triple constituents are resources (due to transparency).
>>>>>>
>>>>>> I believe the following rule does that (given the existing RDF 1.1 entailment):
>>>>>>
>>>>>> If S contains:
>>>>>>
>>>>>>    sss aaa <<(xxx yyy zzz)>> .
>>>>>>
>>>>>> or S contains (in symmetric RDF):
>>>>>>
>>>>>>    <<(xxx yyy zzz)>> aaa ooo .
>>>>>>
>>>>>> then S RDF(1.2)-entails (in symmetric RDF):
>>>>>>
>>>>>>    <<(xxx yyy zzz)>> rdf:type rdf:Proposition .
>>>>>>    <<(xxx yyy zzz)>> rdf:propositionSubject xxx .
>>>>>>    <<(xxx yyy zzz)>> rdf:propositionPredicate yyy .
>>>>>>    <<(xxx yyy zzz)>> rdf:propositionObject zzz .
>>>>>>
>>>>>> Then define:
>>>>>>
>>>>>>    rdf:propositionPredicate rdfs:range rdf:Property .
>>>>>>
>>>>>> To make yyy a property. (Which I think makes sense, even though weird triple terms misusing e.g. classes as properties would have weird consequences.)
>>>>>>
>>>>>>
>>>>>
>>>>> It is a little bit more complicated because of the nesting. We could have
>>>>>
>>>>> :a :b <<( :s :p  <<( :x :y :z )>> )>>.
>>>>>
>>>>> we would want to derive that
>>>>>
>>>>> :y a rdf:Property.
>>>>>
>>>>> But that could still be done with a detailed version of Enrico’s "triple structure appears in“ notation. We could still get your triples.
>>>>>
>>>>> Another problem I see with your approach here is that we depend on RDFS while the properties are already derived in RDF and I assume that we want to keep it that way.
>>>>>
>>>>> Another question is whether or not we want the proposition subject, predicate and object, but they could serve the purpose.
>>>>>
>>>>> Kind regards,
>>>>> Dörthe
>>>>>
>>>>>
>>>>>
>>>>
>>
>>
> 

Received on Wednesday, 8 January 2025 17:05:46 UTC