- From: Ashok Malhotra <ashokma@microsoft.com>
- Date: Wed, 30 Jul 2003 14:30:16 -0700
- To: "Stephen Buxton" <stephen.buxton@oracle.com>, <public-qt-comments@w3.org>
Received on Wednesday, 30 July 2003 17:30:31 UTC
Steve: Thanks for your comment. Yes, if fn:min() or fn:max() are passed a sequence consisting only of NaN values, these values are removed. The input is now an empty sequence and, thus, an empty sequence is returned. We have reordered the rules in fn:min() and fn:max() to make this clearer. All the best, Ashok ________________________________ From: public-qt-comments-request@w3.org [mailto:public-qt-comments-request@w3.org] On Behalf Of Stephen Buxton Sent: Monday, June 30, 2003 6:15 PM To: public-qt-comments@w3.org Subject: ORA-FO-MAXMIN 15.3.3 fn:max, 15.3.4 fn:min Functions and Operators, Section 15.3.3 fn:max, 15.3.4 fn:min If a sequence contains only "NaN" values, then the result of fn:max or fn:min is the empty sequence. Is this correct ?
Received on Wednesday, 30 July 2003 17:30:31 UTC