- From: Tom De Nies <tom.denies@ugent.be>
- Date: Thu, 11 Apr 2013 10:04:33 +0200
- To: Provenance Working Group <public-prov-wg@w3.org>
- Message-ID: <CA+=hbbcjPQ+zKmnwe7-9dkHAEoV3+19YPzB4gry=expdOQrBuQ@mail.gmail.com>
Small correction, we need to have enough to guarantee that insertions and removals do not introduce *or remove* any key-entity pairs, other than those specified. I think the two proposed constraints are sufficient for this, unless I'm missing something. 2013/4/11 Provenance Working Group Issue Tracker <sysbot+tracker@w3.org> > PROV-ISSUE-660 (TomDN): Constraints of PROV-Dictionary [PROV-DICTIONARY] > > http://www.w3.org/2011/prov/track/issues/660 > > Raised by: Tom De Nies > On product: PROV-DICTIONARY > > Luc raised some interesting ideas for the constraints. > > Note that we now have this inference: > > https://dvcs.w3.org/hg/prov/raw-file/default/dictionary/Overview.html#membership-insertion-membership-inference > Inference D4 (membership-insertion-membership) Here, KV1 is a set of > key-entity pairs and K1 is the key-set of KV1. > 1. IF prov:hadDictionaryMember(d1, e, k) and > prov:derivedByInsertionFrom(d2, d1, KV1) and k ∉ K1 THEN > prov:hadDictionaryMember(d2, e, k) > 2. IF prov:hadDictionaryMember(d2, e, k) and > prov:derivedByInsertionFrom(d2, d1, KV1) and k ∉ K1 THEN > prov:hadDictionaryMember(d1, e, k) > > (2nd part suggested by Luc) > I do have one immediate question: do we introduce an infinite loop by > doing this? (consequent of 1. appears in antecedent of 2., and vice versa) > Or is this covered by http://www.w3.org/TR/prov-constraints/#overview ? > > This got me thinking. If we have this, do we really need Inference D8? > https://dvcs.w3.org/hg/prov/raw-file/default/dictionary/Overview.html#insertion-removal-membership-inference > > Couldn't we just specify the same constraint as D4, but for removal? > Suggestion: > Inference D... (membership-removal-membership) Here, K1 is a set of keys. > 1. IF prov:hadDictionaryMember(d1, e, k) and prov:derivedByRemovalFrom(d2, > d1, K1) and k ∉ K1 THEN prov:hadDictionaryMember(d2, e, k) > 2. IF prov:hadDictionaryMember(d2, e, k) and prov:derivedByRemovalFrom(d2, > d1, K1) THEN prov:hadDictionaryMember(d1, e, k) > Note that in the second case, k ∉ K1 is always true, otherwise constraint > D9 is violated. > > Do we then have enough to guarantee that insertions and removals do not > introduce any new key-entity pairs, other than those specified? (which is > why we had Inference D8) > I think so, so I'd like to propose this solution. Could we have your > support or objections via mail or on today's call? > > Regards, > Tom > > > > > > > >
Received on Thursday, 11 April 2013 08:05:01 UTC