- From: Paolo Missier <Paolo.Missier@ncl.ac.uk>
- Date: Thu, 12 Jan 2012 10:06:18 +0000
- To: Graham Klyne <graham.klyne@zoo.ox.ac.uk>
- CC: Khalid Belhajjame <Khalid.Belhajjame@cs.man.ac.uk>, Paolo Missier <paolo.missier@newcastle.ac.uk>, "public-prov-wg@w3.org" <public-prov-wg@w3.org>
Graham sorry for letting this slip. To recall, the context is that I am tasked with fixing the alternateOf section of PROV-DM. I have a few comments to yours and Khalid's. Original text copied where needed. My main comment is that I like your axiomatization of the two relations, but it seems to lead to properties that are not exactly what we want. But there is a simple fix. Specifically: > In other words, what I am suggesting is that: > specializationOf(e1,e2) implies alternateOf(e1,e2) that's fine, I have no problems with that. > *BUT*, this is not what the current text allows, since specializationOf is > defined to be anti-symmetric, which means that it is also anti-reflexive: > > forall (a, b) : specializationOf(a,b) => not specializationOf(b,a) > > setting b = a we see that specializationOf(a,a) must be false, since its truth > would give rise to a contradiction. not really. Anti-symmetry is defined differently. I hate to quote wikipedia, as I don't have the provenance of the content handy :-), but it's just convenient, so: http://en.wikipedia.org/wiki/Antisymmetric_relation basically, an anti-symmetric relation can be reflexive so that's not a problem. More interestingly, about transitivity of alternateOf(): I believe we can still save your axiomatization: > alternativeOf(a, b) == exists (c) : > specializationOf(a,c) and > specializationOf(b,c) just by insisting that the set of all entities forms a lattice. In fact, we only need an upper semi-lattice. This does not ensure that > specializationOf(x, y) or specializationOf(y, x) but it does ensure that for each x,y, there is some z such that specializationOf(x, z) and specializationOf(y, z). alternateOf(a,c) follows. Having a top element is quite natural in class hierarchies (see owl:Thing). But this should come as no surprise as all we are doing is re-invent class hierarchies with a a top element. So in summary: - I am fine with your axiomatization, plus the easy condition that entities form an upper semi-lattice. - I think it belongs in PROV-SEM - I am inclined to keep the properties of the two relations as they are. (and yes, more specific may be better than more concrete). are we in agreement? Cheers, -Paolo On 1/6/12 4:44 PM, Graham Klyne wrote: > Paolo, > > I've now looked at the text and am happy with the direction, but have some > niggles with the details... > > First a nit: you say e1 and e2 provide a more *concrete* characterization than > e1. I would say more *specific* rather than more *concrete*. > > For the rest, using Using Khalid's comments as a spingboard: > > On 05/01/2012 18:43, Khalid Belhajjame wrote: >> Hi, >> >> The new Alternate and Specialization records seem to make sense to me. >> >> - Looking at the definitions of *specializationOf* and *alternateOf*, I for few >> seconds was wondering if it is a good idea to define a more general relationship >> that simply says that two entity records are representations of the same entity, >> without specifying if there is difference in abstraction or context. But, I >> changed my mind as a result, and I now think that the general relationship that >> I was looking for is *alternateOf* itself. Indeed, such a relationship seems to >> be usable in both cases, i.e., different abstractions and/or different contexts. >> In other words, what I am suggesting is that: >> specializationOf(e1,e2) implies alternateOf(e1,e2) > > > > Does that make sense? > > > > I think this depends on how the definitions are set up. > > I see specializationOf as a primnitive using which alternativeOf can be defined: > > alternativeOf(a, b) == exists (c) : > specializationOf(a,c) and > specializationOf(b,c) > > My preference is for specializationOf to be reflexive; i.e. > > forall (a) : specializationOf(a, a) > > your result follows from this: > > given: > specializationOf(e1,e2) [per premise] > specializationOf(e2,e2) [per reflexivity] > > we set a=e1, b=e2, c=e2 to satisfy the RHS of alternativeOf definition, hence > have alternativeOf(e1, e2) as you suggest. > > > *BUT*, this is not what the current text allows, since specializationOf is > defined to be anti-symmetric, which means that it is also anti-reflexive: > > forall (a, b) : specializationOf(a,b) => not specializationOf(b,a) > > setting b = a we see that specializationOf(a,a) must be false, since its truth > would give rise to a contradiction. > > Which in turn means that the above proof of your suggested inference does not hold. > > ... > > So my question is this: is there any particular reason to require anti-symmetry > of specializationOf? > > (An alternative would be to modify the definition of alternativeOf, thus: > > alternativeOf(a, b) == exists (c) : > (specializationOf(a,c) or a = c) and > (specializationOf(b,c) or b = c) > > Absent and particular reason to do otherwise, I'd rather go with the simpler > definitions.) > > >> - *alternateOf* is transitive. > I think it should be, but let's see how this plays: > > alternativeOf(a, b) == exists (x) : > specializationOf(a,x) and > specializationOf(b,x) > > alternativeOf(b, c) == exists (y) : > specializationOf(b,y) and > specializationOf(c,y) > > If we can show specializationOf(x, y) or specializationOf(y, x) then the result > can be derived using transitivity of specializationOf and the definition of > alternativeOf. > > We have: > specializationOf(b,x) and > specializationOf(b,y) > > Intuitively a specializationOf relation holds between x and y as their is a > single non-branching path from b to the "top" of the specialization tree. But I > think we need more stated constraints to derive this. > > Right now, I'm not sure how best to capture this, and am thinking that simply > asserting the required relation would be easiest; i.e. > > specializationOf(b,x) and > specializationOf(b,y) > |= > specializationOf(x,y) or specializationOf(y,x) > > (If specialization is anti-reflexive, we need to add "or x = y" to the above > constraint.) > > Or maybe: > > specializationOf(b,x) and > specializationOf(b,y) > |= > exists (z) : specializationOf(x,z) and specializationOf(y,z) > > An alternative would be to not care about this, in which case alternativeOf is > not inferrable from specializationOf. Does this actually matter? > > #g > -- > >> On 15/12/2011 15:25, Paolo Missier wrote: >>> Hi, >>> >>> in response to the comments about complementarity on the wiki and on the list, >>> we have prepared a revised version of the section, >>> where "complementarity" disappears in favour of "viewOf", and the definition >>> is hopefully simplified and more in line with the >>> expectations: >>> http://dvcs.w3.org/hg/prov/raw-file/default/model/ProvenanceModel.html#record-complement-of >>> (the anchor name hasn't changed :-)) >>> >>> this is for feedback as per today's agenda >>> >>> atb -Paolo >>> >>> >> -- ----------- ~oo~ -------------- Paolo Missier - Paolo.Missier@newcastle.ac.uk, pmissier@acm.org School of Computing Science, Newcastle University, UK http://www.cs.ncl.ac.uk/people/Paolo.Missier
Received on Thursday, 12 January 2012 10:11:49 UTC