- From: Anne van Kesteren via GitHub <sysbot+gh@w3.org>
- Date: Mon, 01 Feb 2021 15:39:18 +0000
- To: public-device-apis-log@w3.org
Yeah, though you want to audit all callers, e.g., `release()` will need to queue a task from its "in parallel" section (although is all it does there queue a task or would it also do some kind of permission check?). It would have to anyway as "release a wake lock" tries to access all kinds of state not typically available "in parallel". -- GitHub Notification of comment by annevk Please view or discuss this issue at https://github.com/w3c/screen-wake-lock/issues/293#issuecomment-770947820 using your GitHub account -- Sent via github-notify-ml as configured in https://github.com/w3c/github-notify-ml-config
Received on Monday, 1 February 2021 15:39:20 UTC