- From: G. Ken Holman <gkholman@CraneSoftwrights.com>
- Date: Thu, 03 Feb 2005 14:45:43 -0500
- To: xmlschema-dev@w3.org
It appears that one cannot redefine a type and leave the mixed= nature of
the original type untouched, which would be important if it were not known
or, more important, arbitrary.
Looking at Part 1, Section 3.4.2, mixed= on <xsd:complexType> has a default
value of false.
Consider I might have a type with mixed content:
<xsd:complexType name="abcType" mixed="true">
<xsd:attribute ...>
...
Now, I redefine that type in an importing schema fragment:
<xsd:redefine ...>
<xsd:complexType name="abcType">
<xsd:complexContent>
<xsd:extension base="abcType">
...
The standard states there is an implicit mixed="false" because of the
default value. This turns off my mixed content, when all I wanted to do
was extend the existing type with some elements.
In this case I know I can just add mixed="true" in the redefinition to
ensure the content is mixed ... but am I missing a way in which I can
redefine a type while preserving its mixed= property?
My guess is no, because if I wanted to turn off the mixed content property
I would intuitively say mixed="false" ... but my intuition to leave it
unchanged is to leave the attribute absent ... but when absent the default
value forces the redefinition to not be mixed. So, it appears I have to
know a priori that a given type I'm redefining is mixed or not and the
burden is on me to preserve it.
Have I read anything incorrectly in this regard?
Thanks for any guidance.
............................... Ken
--
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Received on Thursday, 3 February 2005 19:46:41 UTC