- From: Jean-Jacques Moreau <moreau@crf.canon.fr>
- Date: Mon, 18 Mar 2002 11:30:49 +0100
- To: Martin Gudgin <marting@develop.com>
- CC: "Williams Stuart" <skw@hplb.hpl.hp.com>, Noah Mendelsohn <noah_mendelsohn@us.ibm.com>, XML Protocol Discussion <xml-dist-app@w3.org>
So you are essentially collapsing/folding the terminal nodes into their edges?
Wouldn't the alternate graph below be more symmetric?
Jean-Jacques.
Martin Gudgin wrote:
> <structA>
> <edgeB>terminalB</edgeB>
> <edgeC>terminalC</edgeC>
> <edgeD>
> <structE>
> <edgeF>terminalF</edgeF>
> <edgeG>terminalG</edgeG>
> </structE>
> </edgeD>
> </structA>
<structA>
<edgeB><term>terminalB</term></edgeB>
<edgeC><term>terminalC</term></edgeC>
<edgeD>
<structE>
<edgeF><term>terminalF</term></edgeF>
<edgeG><term>terminalG</term></edgeG>
</structE>
</edgeD>
</structA>
Received on Monday, 18 March 2002 05:32:30 UTC