- From: Jean-Jacques Moreau <moreau@crf.canon.fr>
- Date: Mon, 18 Mar 2002 11:30:49 +0100
- To: Martin Gudgin <marting@develop.com>
- CC: "Williams Stuart" <skw@hplb.hpl.hp.com>, Noah Mendelsohn <noah_mendelsohn@us.ibm.com>, XML Protocol Discussion <xml-dist-app@w3.org>
So you are essentially collapsing/folding the terminal nodes into their edges? Wouldn't the alternate graph below be more symmetric? Jean-Jacques. Martin Gudgin wrote: > <structA> > <edgeB>terminalB</edgeB> > <edgeC>terminalC</edgeC> > <edgeD> > <structE> > <edgeF>terminalF</edgeF> > <edgeG>terminalG</edgeG> > </structE> > </edgeD> > </structA> <structA> <edgeB><term>terminalB</term></edgeB> <edgeC><term>terminalC</term></edgeC> <edgeD> <structE> <edgeF><term>terminalF</term></edgeF> <edgeG><term>terminalG</term></edgeG> </structE> </edgeD> </structA>
Received on Monday, 18 March 2002 05:32:30 UTC