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RE: Issue-57

From: Larry Masinter <masinter@adobe.com>
Date: Mon, 27 Jun 2011 00:05:14 -0700
To: Tore Eriksson <tore.eriksson@po.rd.taisho.co.jp>, Jonathan Rees <jar@creativecommons.org>
CC: "www-tag@w3.org" <www-tag@w3.org>
Message-ID: <C68CB012D9182D408CED7B884F441D4D05CAF7CBE4@nambxv01a.corp.adobe.com>
>     <http://example/z> xhv:license <http://example/l1>.
>  Suppose that I do a GET of 'http://example/z' and retrieve a "representation" R.
>  My interlocutor wants me to be able to infer that
>   R xhv:license <http://example/l1>.

I'm wondering about this inference, and its possible relationship to the copyright/deep linking issue we've been talking about recently.
Seems to me that whether you can make that inference depends on the license l1, and that there are some licenses for which the inference is not true, because the license applies to the material _at_ the URI.

For example,

"You are licensed to transclude or view or print the content from <http://example/z> but not republish it at a different URL than the one you found it at?"

 Such that the license really applies to http://example/z but not to R itself? 

Or, to take the "deep linking" case:

"the license for <http://example/z> only allows access if one first accesses <http://example/homepage> and clicks on the link there" ?

There are some licenses we think are reasonable, and some licenses we think are _not_ reasonable, but ... how would you write a license that disallowed deep linking? 

Of course, you could write a license that allowed reuse of R, but perhaps that might be explicit:

"whatever content is located at the URI given,  that content may be used in the following ways".

and that license l2 would read the same, but instead start

   "the content given may be used in the following ways".

and you could infer

     R xhv:license <http://example/l2>

Received on Monday, 27 June 2011 07:06:12 UTC

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