- From: Tab Atkins Jr. <jackalmage@gmail.com>
- Date: Mon, 17 Aug 2009 20:58:53 -0500
- To: fantasai <fantasai.lists@inkedblade.net>
- Cc: www-style@w3.org
On Mon, Aug 17, 2009 at 5:34 PM, fantasai<fantasai.lists@inkedblade.net> wrote: > Tab Atkins Jr. wrote: >> >> On Mon, Aug 17, 2009 at 3:54 PM, fantasai<fantasai.lists@inkedblade.net> >> wrote: >>> >>> Brad Kemper wrote: >>>> >>>> On Aug 17, 2009, at 11:00 AM, fantasai <fantasai.lists@inkedblade.net> >>>> wrote: >>>> >>>>> I would prefer restricting stops to percentages. The swapping effect >>>>> is confusing, and I don't see any reason you'd /need/ to use lengths >>>>> when you can specify the length of the overall gradient already. >>>> >>>> I can think of plenty of situations where I'd want the whole gradient >>>> to >>>> be a fixed distance, regardless of box size, and regardless of angle. >>>> I'd >>>> like to be able to set that in a simple grammar, using color-stops only. >>>> It's not nearly as simple if the angle is not a multiple of 90, and I >>>> have >>>> to use bg-position. >>> >>> This is not simple? >>> >>> linear-gradient(top left 135deg 200px / red, white, blue) >>> /* linear gradient from top left corner angled at 135deg going for 200px >>> transitioning from red to white to blue */ >> >> That requires an *additional* argument to the angle construction. >> It's equally easy to do: >> >> linear-gradient(135deg / red, white, blue 200px) > > Which requires an additional argument to the last color construction. :) Ah, but it's an argument that's already included in the syntax. > Is the 200px offset from the beginning of the gradient or from the > last color stop? I'm not totally clear on this. (I find it easier > to think of the entire gradient being 200px long and then filling > in the color stops than positioning the last color stop and then > filling in the color stops backwards from there.) All color-stop lengths and % measure from the beginning. >> (You probably meant an angle other than 135deg, btw. That points up >> into the top-left, and would currently result in a pure-blue gradient >> as the starting and ending points are identical.) > > Heh, okay. I wasn't sure which direction 0deg was pointing. > For several other properties (e.g. image-orientation) it's up. Well, not really. The angle in image-orientation describes a rotation, not a direction. It just reuses SVG's definition of positive angles meaning a CW rotation, which is a little confusing. But doing *anything* other than 0deg=East, 90deg=North for actual directional angles would be extremely confusing as well. I'll make it explicit. ~TJ
Received on Tuesday, 18 August 2009 01:59:48 UTC