- From: <Toman_Vojtech@emc.com>
- Date: Fri, 22 Aug 2008 10:27:00 -0400
- To: <public-xml-processing-model-wg@w3.org>
>
> Imagine that library.xpl contains:
>
> <p:library ...>
> <p:declare-step name="xinclude-and-xslt">...</p:declare-step>
> </p:library>
>
> Consider the following imaginary command line syntax:
>
> $ calabash -isource=- -oresult=- -s xinclude-and-xslt library.xpl
>
> This tells the processor to load "library.xpl" and run the step named
> "xinclude-and-xslt". All straightforward.
>
> Now suppose I want to just run the "add-attribute" step. I could wrap
> it in a pipeline, put it in a library, give it a name, and run it. But
> since the library for the XProc builtin steps is always loaded (at
> least conceptually), why do I have to do that? Why can't I just say:
>
> $ calabash -isource=- -oresult=- -s add-attribute \
> match=div attribute-name=foo attribute-value=bar
>
> I can't because the standard p:add-attribute step doesn't have a name.
>
Can't you do something like this on the command line:
$ calabash -isource=- -oresult=- -s p:add-attribute \
-xmlns:p=http://www.w3.org/ns/xproc \
match=div attribute-name=foo attribute-value=bar
You don't need to give the step a name in this case, and it is also more
consistent with the way you would invoke the step in an XProc pipeline.
The step names are "local" in nature - if you import a library in a
pipeline, the step names are invisible in the target context, so the
pipeline does not see the names of the imported steps, only their types.
So, in my opinion, I think that using step types instead of names on the
command line is more correct.
Regards,
Vojtech
Received on Friday, 22 August 2008 14:27:55 UTC