On 13/11/2009 07:18, Axel Polleres wrote: > One concern raised was IIRC why we need both if HAVING is anyway redundant by: > > SELECT AGG(?X) > WHERE P > GROUP BY G > HAVING R > > being equivalent to > > { SELECT AGG(?X) > WHERE P > GROUP BY G } > FILTER R Can R be (count(*)>0) ? Andy > > which would HAVING really make the very same as FILTER in the end of th the day. > Can we confirm/decline this (conjectured) equivalence? > > > best, > AxelReceived on Friday, 13 November 2009 11:53:24 UTC
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