- From: imikhailov <imikhailov@openlinksw.com>
- Date: Wed, 28 Dec 2005 23:50:11 +0600
- To: <public-rdf-dawg-comments@w3.org>
Hello,
Let's try to use the SPARQL grammar rule
[80] STRING_LITERAL_LONG1 ::=
"'''" ( [^'\] | ECHAR | ("'" [^']) | ("''" [^']) )* "'''"
to parse a string '''some-plain-text''\\more-plain-text'''
It seemes to me that it is parsed as
-- starting "'''";
-- "some-plain-text", in a char-by-char loop,
-- "''\", matching ("''" [^']),
-- "\m", oops, this does not match ECHAR.
-- ore-plain-text''' is parsed by error recovery code.
I believe that the proper formal notation is
[80] STRING_LITERAL_LONG1 ::=
"'''" ( ("'" ("'"?))? ([^'\] | ECHAR) )* "'''"
Unfortunately, this is less readable.
Best Regards,
Ivan Mikhailov
OpenLink Software.
Received on Friday, 30 December 2005 08:14:04 UTC