- From: <bugzilla@jessica.w3.org>
- Date: Sun, 05 Jul 2015 20:58:36 +0000
- To: public-qt-comments@w3.org
https://www.w3.org/Bugs/Public/show_bug.cgi?id=28901 --- Comment #1 from Michael Kay <mike@saxonica.com> --- In 3.11.13.2 we read The semantics of E?S are equivalent to for $a in E, $b in S return $a($b) , where E is an expression on the left of the postfix ? operator and ?S is the unary lookup operator described in 3.11.3.1 Unary Lookup. This doesn't work. "?S" isn't a unary lookup operator. I think this should be The semantics of E?S are equivalent to for $a in E return $a ! ?S where ?S uses the unary lookup operator described in 3.11.3.1 Unary Lookup -- You are receiving this mail because: You are the QA Contact for the bug.
Received on Sunday, 5 July 2015 20:58:39 UTC