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[Bug 24537] Ambiguous rule #4 in union, intersect, except expressions streamability

From: <bugzilla@jessica.w3.org>
Date: Thu, 06 Feb 2014 17:58:09 +0000
To: public-qt-comments@w3.org
Message-ID: <bug-24537-523-mcBLZdS0rp@http.www.w3.org/Bugs/Public/>
https://www.w3.org/Bugs/Public/show_bug.cgi?id=24537

Michael Kay <mike@saxonica.com> changed:

           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|NEW                         |RESOLVED
         Resolution|---                         |FIXED

--- Comment #1 from Michael Kay <mike@saxonica.com> ---
It's intended to mean 

if (every operand O satisfies (O is crawling or O is striding))

I think a different reading would be hard to justify, and I guess the example
was added just in case there was any doubt. It's a bit difficult to find a more
rigorous wording that isn't turgid to read, but I'll go with

if the first operand is striding or crawling and the second operand is also
striding or crawling, then...

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Received on Thursday, 6 February 2014 17:58:10 UTC

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