- From: <bugzilla@wiggum.w3.org>
- Date: Wed, 20 May 2009 15:22:26 +0000
- To: public-qt-comments@w3.org
http://www.w3.org/Bugs/Public/show_bug.cgi?id=6927 Summary: XQuery 1.1 is not an LL(k) language because of the optional "outer" keyword Product: XPath / XQuery / XSLT Version: Working drafts Platform: All OS/Version: All Status: NEW Severity: major Priority: P2 Component: XQuery 1.1 AssignedTo: jonathan.robie@redhat.com ReportedBy: gabriel.petrovay@28msec.com QAContact: public-qt-comments@w3.org Hi all, XQuery 1.1 is not an LL(k) language because of the optional "outer" keyword (yes I know XQuery has no keywords). Take the following 2 correct queries: 1. for $x in outer for $y in Expr return 2 2. for $x in outer for $y in Expr return 2 return 3 The parser has a problem when parsing the "outer for" token sequence because it does not know which production to take next because of the OPTIONAL "outer" keyword. Is it a nested "outer for" or the "outer" step expression followed by a simple "for" clause? Of course that, by reading the whole input you can determine if the expression is correct, but the language is not anymore an LL(k) one. This is because for any k > 0, one can find an expression (Expr) having [number of tokens] > k such that the parser cannot parse the language. Regards, Gabriel -- Configure bugmail: http://www.w3.org/Bugs/Public/userprefs.cgi?tab=email ------- You are receiving this mail because: ------- You are the QA contact for the bug.
Received on Wednesday, 20 May 2009 15:22:35 UTC