- From: Matthew Fuchs <matt@westbridgetech.com>
- Date: Fri, 12 Mar 2004 11:08:11 -0800
- To: <public-qt-comments@w3.org>
- Message-ID: <001f01c40865$5fb60520$7364020a@westbridgetech.com>
I'm trying to understand if it is possible to use <xsl:sequence> to return nodes, specifically elements, from the source document. Without getting into the use case behind this, I read both the latest public working draft and the current working draft as saying that in the following: <xsl:variable name="foo" select="somepath"/> and <xsl:variable name="foo"> <xsl:sequence select="somepath"/> </xsl:variable> $foo will be assigned equivalent nodes from the source document (in particular, if the result is some descendant of the root, then I can apply parent or ancestor axes and get the same results). If that's the case, is it further the case (here's the real interesting part) that I can put the <xsl:sequence> in a template, i.e., <xsl:variable name="foo"> <xsl:apply-templates select="." mode="test"/> </xsl:variable> <xsl:template match=".element." mode="test"> <xsl:sequence select="somepath"/> </xsl:template> and, once again, get back an equivalent node? Thank you, Matthew Fuchs
Received on Friday, 12 March 2004 14:09:46 UTC