- From: Oliver Becker <obecker@informatik.hu-berlin.de>
- Date: Fri, 26 Sep 2003 10:48:50 +0200 (MEST)
- To: public-qt-comments@w3.org, jean.huberson@free.fr
- Cc: christian.huberson@imag.fr
> I have been working with XSLT files quite a lot and I think that a function
> that could give the absolute path of the current node would be very useful
> in cases where you have no idea about the structure of the XML file you are
> processing.
> The result returned by the "path()" function would look something like this:
> "/book/chapter[2]/paragraph[5]/title"
Perhaps you want
string-join(for $n in ancestor-or-self::* return ('/', name($n), '[',
string(count($n/preceding-sibling::*[name()=name($n)])+1), ']'), '')
(this is an extension of the [fixed] string-joing example in the
Functions and Operators specification)
Note also the fn:node-kind function in case you want to know the type
of the current node.
Cheers,
Oliver
(Not a member of the WG, so actually I shouldn't have responded ... ;-)
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| ob|do Dipl.Inf. Oliver Becker |
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Received on Friday, 26 September 2003 04:49:17 UTC