On Wed, 11 Jul 2007, Geoffrey Sneddon wrote: > > Passing #lists a string of "10" results in a list with a single value: > 1. This (almost certain) bug is caused by substeps 2–4 of the number > character option within step 13 (parser). At the second digit, we > multiple 0*10 before adding it to value. However, if we rewrite this set > of substeps to follow the pattern used in the algorithms above (such as > real numbers) the said bug can be fixed: > > [[ > 1. If finished is true, skip to the next step in the overall set of steps. > > 2. Multiply value by ten. > > 3. Add the value of the digit, interpreted in base ten, to value. > > 4. Let started be true. > ]] > > This removes the need for two variables (multiple and n). Therefore, > step 9 of the outer algorithm also needs to be removed. Er, yeah, I don't know what I was thinking about when I was writing that part of the algorithm, but it clearly wasn't maths. Fixed. -- Ian Hickson U+1047E )\._.,--....,'``. fL http://ln.hixie.ch/ U+263A /, _.. \ _\ ;`._ ,. Things that are impossible just take longer. `._.-(,_..'--(,_..'`-.;.'Received on Thursday, 8 May 2008 06:08:40 UTC
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