- From: Kinkie <gkinkie@gmail.com>
- Date: Thu, 3 Jul 2014 08:19:24 +0200
- To: Matthew Kerwin <matthew@kerwin.net.au>
- Cc: HTTP Working Group <ietf-http-wg@w3.org>, Martin Thomson <martin.thomson@gmail.com>
- Message-ID: <CA+Y8hcPNtJCXp0U9H0R+Hm3yFh2yLR_aKh5mzqJ108dk5v6giw@mail.gmail.com>
Hi Matthew., On Jul 3, 2014 8:11 AM, "Matthew Kerwin" <matthew@kerwin.net.au> wrote: > > On 3 July 2014 15:02, Kinkie <gkinkie@gmail.com> wrote: >> >> The selection algorithm can then be specified pretty simply: clients SHOULD choose randomly one alternate server but it MUST be among the pool having the highest-priority value. > > > If the client MUST choose from the highest priority pool, why would the server ever bother sending those with lower values? Unless you're suggesting the server-supplied q-values are combined with some client-side preference metric to provide the final priority (a la RFC 2296)? Or are you considering that, if the client attempts all the highest-priority alternates and they fail, it can then move onto the lower priorities? I'm suggesting the latter. See the use case I gave in a different mail in this thread. > > >> It can be debated whether clients can retry to a different server requests not having any side effects, but in that case the algorithm should be pretty much the same as in the first round, after invalidating the failed server(s). >> >> I would not overload max-age however with this task however. If a "q=" parameter can be added, it should be possible to add a "max-age=" parameter as well, isn't it? Unless the proposal is to define some mechanism to clear the list of altsvc regardless of any other expiry information. > > > There's already a max-age ("ma") parameter "which indicates the number of seconds [...] the alternative service is considered fresh for", the default being 24 hours. Setting it to 0 automatically marks the alternate service as stale, which I suppose means it's no longer available. That means being able to send a second Alt-Svc header with the same [protocol,host,port] tuple, but with "ma=0". Thanks for clarifying this for me. This would of course work.
Received on Thursday, 3 July 2014 06:19:52 UTC