- From: Michael Kay <mike@saxonica.com>
- Date: Tue, 19 Dec 2006 14:57:29 -0000
- To: "'Fortuno, Adam'" <Adam_Fortuno@ghrsystems.com>, <xmlschema-dev@w3.org>
You want something like this: <xs:element name="Foo"> <xs:complexType> <xs:simpleContent> <xs:restriction base="xs:token"> <xs:enumeration value="ABC" /> <xs:enumeration value="123" /> <xs:enumeration value="DEF" /> </xs:restriction> </xs:simpleContent> <xs:attribute name="_Code" type="xs:string"/> </xs:complexType> </xs:element> ALternatively you can define the type of Foo as an extension of FooType (extended by adding an attribute) Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: xmlschema-dev-request@w3.org > [mailto:xmlschema-dev-request@w3.org] On Behalf Of Fortuno, Adam > Sent: 15 December 2006 19:26 > To: xmlschema-dev@w3.org > Subject: Element Takes Enumerated List but has Attribute that > Takes a String > > > All, > > I'm trying to create the below structure > > <Foo _Code="XYZ">ABC</Foo> > > Where the element `Foo` takes a literal value from an > enumerated list, and the attribute `_Code` takes a > (xs:)string. I have tried a few different constructs based on > research I've done. I can get the enumerated list for the > element but not the attribute or vice versa. > > Any suggestions would be appreciated. Here is what I've tried > (doesn't work). > > <xs:element name="Foo" type="FooType"> > <xs:complexType> > <xs:attribute name="_Code" type="xs:string"/> > </xs:complexType> > </xs:element> > <xs:simpleType name="FooType"> > <xs:restriction base="xs:token"> > <xs:enumeration value="ABC" /> > <xs:enumeration value="123" /> > <xs:enumeration value="DEF" /> > </xs:restriction> > </xs:simpleType> > > Regards, > Adam > >
Received on Tuesday, 19 December 2006 14:57:37 UTC