- From: Stefan Wachter <Stefan.Wachter@gmx.de>
- Date: Thu, 26 Sep 2002 13:25:13 +0200 (MEST)
- To: abdolah@freenet.de;xmlschema-dev@w3.org;;
I think you should post questions regarding stylesheets in other lists.
However, I think your problem is solved with the following template:
<template match="node()">
<copy><text>
</text>
<apply-templates/>
</copy>
</template>
--Stefan
>
> hello,
> I'm working with saxon to Transform xsl/xml-file to Text-Format
> In the Head of my xsl-stylesheet i used:
> <?xml version="1.0" encoding="iso-8859-1"?>
> <xsl:stylesheet version="1.0"
> xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
> <xsl:output method="text" indent="yes"/>
> .....
> As Rsesult of transformation i get:
> line1line2line3line4line5...........
> I' will but to get all breaks in my document :
> line1
> line2
> line3
> ........
> could somebody help me, how i get all line-breaks in my resultfile?
> I thank at advance
> A.A
>
>
>
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Received on Thursday, 26 September 2002 07:25:48 UTC