- From: <qyz@clickmarks.com>
- Date: Fri, 16 Nov 2001 10:52:26 -0500 (EST)
- To: <xmlschema-dev@w3.org>
Hello,
I can't figure out a way to extend a type which
has an empty content model to create a sub-type with a simple content
model. The problem is that the only way to declare a type with a simple
content model is to restrict a simple type? So I essentially need
multiple inheritance to do this :-(
Example:
<xs:complexType name="PropertyType">
</xs:complexType>
<xs:complexType name="BooleanPropertyType" >
<xs:simpleContent>
<xs:extension base="PropertyType">
<xs:simpleType>
<xs:restriction base="xs:boolean"/>
</xs:simpleType>
</xs:extension>
</xs:simpleContent>
</xs:complexType>
I'm trying to create BooleanPropertyType so that it is a sub-type of
PropertType, with a content model that allows only Boolean values. I know
the above is not valid XML Schema; is there any way to express this? It
seems to me that it should be allowed, because PropertyType has an empty
content model, so a boolean content model should be a valid extension? But
the type declaration doesn't let me specify: type="xs:boolean" (unlike an
element declaration which does allow that). So the only way to declare a
boolean content model is by restricting from "xs:boolean"? Which of
course means I can't derive from another type.
Thanks for any help!
Quinton
Received on Friday, 16 November 2001 11:04:46 UTC