- From: Eddie Robertsson <eddie@allette.com.au>
- Date: Thu, 25 Jan 2001 11:59:40 +1100
- To: Michael Anderson <michael@research.canon.com.au>
- CC: "Kollu, Kishore" <kishore_kollu@mentorg.com>, "Xml-Schema-Dev (E-mail)" <xmlschema-dev@w3.org>
Michael Anderson wrote: > "Kollu, Kishore" wrote: > > > Hi, > > Can I define a list element with an attribute? If so how? > > > > I would like to have an element like : > > > > <terminals n="4">t1 t2 t3 t4</terminals> > > Sure, create a complexType with simpleContent that extends your list > SimpleType by adding an attribute. See the Primer Sections 2.3.1 and > 2.5.1. Example: <?xml version="1.0" encoding="UTF-8"?> <xsd:schema xmlns:xsd="http://www.w3.org/2000/10/XMLSchema" elementFormDefault="qualified" targetNamespace="www.terminal.org" xmlns="www.terminal.org"> <xsd:simpleType name="terminalType"> <xsd:restriction base="xsd:string"> <xsd:pattern value="t\d+"/> </xsd:restriction> </xsd:simpleType> <xsd:simpleType name="terminalList"> <xsd:list itemType="terminalType"/> </xsd:simpleType> <xsd:complexType name="terminals"> <xsd:simpleContent> <xsd:extension base="terminalList"> <xsd:attribute name="n" type="xsd:positiveInteger"/> </xsd:extension> </xsd:simpleContent> </xsd:complexType> <xsd:element name="terminal" type="terminals"/> </xsd:schema> /Eddie
Received on Wednesday, 24 January 2001 19:57:12 UTC