- From: David Turner <novalis@fsf.org>
- Date: Thu, 05 Aug 2004 12:34:27 -0400
- To: www-svg@w3.org
I'm trying to implement proper direcionality for path markers in Inkscape (the current version is entirely nonconforming). Here's what 11.6.2 tells me: "(a) if there is a path segment coming into the vertex and another path segment going out of the vertex, the marker's positive x-axis should point toward the angle bisector for the angle at the given vertex, where that angle has one side consisting of tangent vector for the path segment going into the vertex and the other side the tangent vector for the path segment going out of the vertex ..." Question: What is the tangent vector to the initial point of a curve, when the first control point is identical to the initial control point? My guess (based on eyeballing the curves onscreen) would be to devolve to the direction from the initial point to the second control point, then to the end point, then to the rules for zero-length path segments (in the implementation notes). Is this correct? I'm not subscribed to the mailing list, so please CC me on replies. -- -Dave Turner GPL Compliance Engineer Support my work: http://svcs.affero.net/rm.php?r=novalis&p=FSF
Received on Thursday, 5 August 2004 12:38:39 UTC