- From: Simon Pieters <simonp@opera.com>
- Date: Mon, 24 Feb 2014 14:01:56 +0100
- To: "Tab Atkins Jr." <jackalmage@gmail.com>, "Jirka Kosek" <jirka@kosek.cz>
- Cc: "Simon Sapin" <simon.sapin@exyr.org>, www-style <www-style@w3.org>
On Wed, 19 Feb 2014 08:56:41 +0100, Jirka Kosek <jirka@kosek.cz> wrote: > On 19.2.2014 1:43, Tab Atkins Jr. wrote: >>>> If the prefix is omitted, the selector only matches attributes in no >>>> namespace. >>> >>> … which applies to both ::attr(foo) and ::attr(*) >>> >>> I like the consistency, but it means that "give me all the things" >>> must be >>> written ::attr(*|*) rather than just ::attr(*), which doesn’t seem to >>> be >>> what Jirka wanted. >> >> That's consistent with what Selectors does for type selectors, though. >> I'd be extremely loathe to break that consistency. > > I'm not sure with what you are trying to be consistent, if with the > following from the Selectors: > > "* > if no default namespace has been specified, this is equivalent to *|*. > Otherwise it is equivalent to ns|* where ns is the default namespace." > > Then I have to point out that default namespace does not apply to > attributes, so it doesn't make sense to align * behaviour for attributes > with elements. > > Or had you in mind something different? I'm not Tab but I think the reasoning is as follows: * and foo are equivalent for the namespace part, i.e. same as *|* and *|foo or ns|* and ns|foo hence ::attr(*) and ::attr(foo) should also be equivalent for the namespace part, i.e. same as ::attr(|*) and ::attr(|foo) -- Simon Pieters Opera Software
Received on Monday, 24 February 2014 13:02:28 UTC