On Wed, 19 Feb 2014 08:56:41 +0100, Jirka Kosek <jirka@kosek.cz> wrote: > On 19.2.2014 1:43, Tab Atkins Jr. wrote: >>>> If the prefix is omitted, the selector only matches attributes in no >>>> namespace. >>> >>> … which applies to both ::attr(foo) and ::attr(*) >>> >>> I like the consistency, but it means that "give me all the things" >>> must be >>> written ::attr(*|*) rather than just ::attr(*), which doesn’t seem to >>> be >>> what Jirka wanted. >> >> That's consistent with what Selectors does for type selectors, though. >> I'd be extremely loathe to break that consistency. > > I'm not sure with what you are trying to be consistent, if with the > following from the Selectors: > > "* > if no default namespace has been specified, this is equivalent to *|*. > Otherwise it is equivalent to ns|* where ns is the default namespace." > > Then I have to point out that default namespace does not apply to > attributes, so it doesn't make sense to align * behaviour for attributes > with elements. > > Or had you in mind something different? I'm not Tab but I think the reasoning is as follows: * and foo are equivalent for the namespace part, i.e. same as *|* and *|foo or ns|* and ns|foo hence ::attr(*) and ::attr(foo) should also be equivalent for the namespace part, i.e. same as ::attr(|*) and ::attr(|foo) -- Simon Pieters Opera SoftwareReceived on Monday, 24 February 2014 13:02:28 UTC
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