- From: Øyvind Stenhaug <oyvinds@opera.com>
- Date: Tue, 29 Jan 2013 12:14:12 +0100
- To: "Johannes Koch" <koch@w3development.de>, "www-style@w3.org" <www-style@w3.org>, François REMY <francois.remy.dev@outlook.com>
- Cc: Fantasai <fantasai.lists@inkedblade.net>
On Mon, 28 Jan 2013 20:00:43 +0100, François REMY <francois.remy.dev@outlook.com> wrote: >> For instance, if we say the viewing distance is about half an arms >> length >> then the size of a reference pixel would be about 1/128 physical inches. >> Given 312 device pixels per physical inch, this gives 312/128 = 2.4375 >> device pixels per reference pixel. Sorry, as I was waiting for the bus home yesterday it occurred to me that I had written something wrong... I should probably be more careful with arithmetic so late in the afternoon :) Not sure where the 1/128 came from, it should of course be 1/192 (half of 1/96). Though 312/192 = 1.625 still rounds to 2, and with Kenneth's percentages it would as well (60% would give 1.95 and 70% would give 2.275). > Thanks for the clarification. Is there an online calculator that gives > the optimal size of a pixel (or the DPI) given the viewing distance? Not that I know, but it's basically just a linear relationship with a 1/96 inch pixel size at 28 inches viewing distance, as indicated by other posts. -- Øyvind Stenhaug Opera Software ASA
Received on Tuesday, 29 January 2013 11:14:46 UTC