- From: Alan Gresley <alan@css-class.com>
- Date: Sat, 25 Jun 2011 03:49:31 +1000
- To: "Tab Atkins Jr." <jackalmage@gmail.com>
- CC: www-style@w3.org
On 9/02/2011 4:44 PM, Tab Atkins Jr. wrote: > On Tue, Feb 8, 2011 at 5:45 PM, Alan Gresley<alan@css-class.com> wrote: >> Something like this perhaps. >> >> >> linear-gradient(left rgba(255,255,0,1), 50% rgba(127,127,63,0.5), >> rgba(0,0,0,0)) > > Yup, something like that. > > ~TJ To be precise, this is what has to be done. linear-gradient(left, yellow, rgba(127,127,0,0.5) 50%, rgba(64,64,0,0.25) 75%, rgba(32,32,0,0.125) 87.5%, rgba(16,16,0,0.0625) 93.75%, rgba(8,8,0,0.03125) 96.875%, rgba(4,4,0,0.015625) 98.4375%, rgba(0,0,0,0)) I presume you understand the maths above and I was able to intuit how to achieve such a gradient but I do believe that such a method to create such a gradient should also be given as an example in the spec since most authors would not know that such gradients are possible when the changes are made in browsers to match IE10 behavior or even know how to do the maths. -- Alan Gresley http://css-3d.org/ http://css-class.com/
Received on Friday, 24 June 2011 17:50:05 UTC