- From: Brian Manthos <brianman@microsoft.com>
- Date: Tue, 11 May 2010 15:59:50 +0000
- To: Brian Manthos <brianman@microsoft.com>, Brad Kemper <brad.kemper@gmail.com>
- CC: "www-style@w3.org" <www-style@w3.org>
- Message-ID: <FA122FEC823D524CB516E4E0374D9DCF014F969F@TK5EX14MBXC136.redmond.corp.microsoft.>
Elaborating... I see 3 different renderings in 3 different browsers, so I’d like to make sure I understand it correctly. From: Brian Manthos Sent: Tuesday, May 11, 2010 8:58 AM To: 'Brad Kemper' Cc: www-style@w3.org Subject: RE: [css3-background] background-size and zero length Where is the rounding rule for the zero case defined? I see it defined for the non-zero case, as you observed as well. Is the zero case rounding rule left as UA-defined? I’m not clear on how to follow this rule without an equation or having it specified in prose: If ‘background-repeat<http://dev.w3.org/csswg/css3-background/#background-repeat>’ is ‘round’ for one (or both) dimensions, there is a second step. The UA must scale the image in that dimension (or both dimensions) so that it fits a whole number of times in the background positioning area. Thanks, -Brian From: Brad Kemper [mailto:brad.kemper@gmail.com] Sent: Tuesday, May 11, 2010 8:39 AM To: Brian Manthos Cc: www-style@w3.org Subject: Re: [css3-background] background-size and zero length On May 11, 2010, at 7:04 AM, Brian Manthos wrote: Typo. Mea culpa. The style rule should have been... div { background: url(http://www.microsoft.com/favicon.ico) 5px 5px; background-size: 0px 20px; background-repeat:round; width:12px; height:17px; } -Brian [...] How many images should be rendered and at what size? An infinite number, with zero width for each tile. Rounding does not change that, because the "If X ≠ 0 is the width of the image after step one" part is not fulfilled. A tile with no width or no height cannot be drawn, so you shouldn't try. That's how I understand it, anyway.
Received on Tuesday, 11 May 2010 16:01:42 UTC