- From: Mike Wilson <mikewse@hotmail.com>
- Date: Sat, 14 Mar 2009 14:44:35 +0100
- To: "'www-style'" <www-style@w3.org>
Pardon me if this have been covered before, but has there been any discussion on whether :nth-child (and other structural selectors) should be able to work on indexes from the selected child subset rather than from the 'complete' child list? Example targeting all <li>s: li.item:nth-child(odd) {background-color:grey;} <li class="item">a</li> --> index 1 = odd = grey <li class="item">b</li> --> index 2 = even <li class="item">c</li> --> index 3 = odd = grey Example targeting subset of <li>s: li.item:nth-child(odd) {background-color:grey;} <li>...</li> --> index 1 (not selected) <li class="item">a</li> --> index 2 = even <li class="item">b</li> --> index 3 = odd = grey <li class="item">c</li> --> index 4 = even In the second example we see that the first <li> "consumes" the first odd entry from the formating rule, although it is not selected by this rule. This makes the whole striped formating visually shift one step forward as a side effect of introducing an element not covered by the rule. Would it be desirable to instead count indexes based on the selected subset, like in: li.item:nth-child(odd) {background-color:grey;} <li>...</li> --> (not selected) <li class="item">a</li> --> index 1 = odd = grey <li class="item">b</li> --> index 2 = even <li class="item">c</li> --> index 3 = odd = grey ? Best regards Mike Wilson
Received on Saturday, 14 March 2009 13:45:45 UTC