Re: border-radius

>> The proposed "innermost radius wins" rule doesn't have this problem 
>> in addition to being consistent with the color rule. 
 
> So far, the innermost radius is zero. Are you saying that if the TD 
> has a zero radius and the table has a non-zero radius, that the zero
> should always win because it is smaller?
> 
> I think the largest should win.

No, with "innermost radius wins", I mean that the radius of the cell 
should win.

Let the largest (or smallest) radius win is another rule we should 
consider.

Nick



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