- From: Jule Kleine <listmail@web.de>
- Date: Tue, 16 Aug 2005 13:07:41 +0200
- To: www-ql@w3.org
Hi, I would like to check, if the name of the second element of a parent element is "youngestSon". Is it possible to query this with xpath/xquery (I use xquery with xpath-expressions, in fact I already know the name of the element but want to get sure with an exist-statement, that the element's position is 2) ? <parent> <oldestSon>A</oldestSon> <youngestSon>B</youngestSon> </parent> Note, that the child element names are different. What I dont need is the second son in the following example (therefor I could use /parent/son[position()==2] ) <parent> <son>A</son> <son>B</son> </parent> ---- My XQuery is: xquery version "1.0"; for $parent in doc("sample.xml")/parent let $oldestson:= $parent/oldestSon let $youngestson:= $parent/youngestSon where ( exists($parent) and exists($oldestson) and exists($youngestson) ) return ( <success/> ) ----- The Query checks, if in the sample-document there exists a parent with oldestSon and youngestSon, but doesnt make sure, that oldestSon comes before youngestSon. I could use where $oldestson < $youngestson but have cases where I dont know all elements (and therefor nothing about oldestson), so would like something like where $youngestson "IS SECOND CHILD OF PARENT" Thank you for any help!!! Jule Thank you for any help! Jule _________________________________________________________________________ Mit der Gruppen-SMS von WEB.DE FreeMail können Sie eine SMS an alle Freunde gleichzeitig schicken: http://freemail.web.de/features/?mc=021179
Received on Tuesday, 16 August 2005 11:07:47 UTC