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[Bug 16638] New: Define who owns what with MutationObserver

From: <bugzilla@jessica.w3.org>
Date: Thu, 05 Apr 2012 06:33:23 +0000
To: www-dom@w3.org
Message-ID: <bug-16638-4009@http.www.w3.org/Bugs/Public/>

           Summary: Define who owns what with MutationObserver
           Product: WebAppsWG
           Version: unspecified
          Platform: PC
        OS/Version: Linux
            Status: NEW
          Severity: normal
          Priority: P2
         Component: DOM
        AssignedTo: annevk@opera.com
        ReportedBy: Olli.Pettay@gmail.com
         QAContact: public-webapps-bugzilla@w3.org
                CC: mike@w3.org, jonas@sicking.cc, www-dom@w3.org,
                    adamk@chromium.org, rafaelw@chromium.org

Should MutationObserver own the nodes it is observing?
I think not. If JS doesn't have a pointer to the node, it can't
modify it.
But if the original observe target is deleted, what should happen
to the transient observers? I think they should still work (until the end of
the microtask). That way GC/CC behavior isn't visible to the API user.

Then MutationObserver object itself... I think the only way to hide GC/CC
behavior is to keep MutationObserver object alive as long as
the node(s) it is observing is/are alive.

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Received on Thursday, 5 April 2012 06:33:26 UTC

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