Re: Making all interactive elements visible

Ian,

Okay, I see that's a pretty good solution.

The only problem I have with

   A[onmouseover] { background: yellow; color: black }
is that I don't think it supports mouseovers that come from script, such as:

function addMouseOvers()
{
var nodeList = document.getElementsByTagName('TD');
var endList=nodeList.length;
for (var count =0; count < endList; count++) {
  node=nodeList[count];
  // Using setAttribute instead of AddEventListener gets around bug where
  // the mouseover in the tablecell is ignored when you're over the text inside the cell
  node.addEventListener('mouseover',showTheSquare, false );
  }
}

I think this will be quite common.

Aaron



Ian Jacobs wrote:

> Aaron Leventhal wrote:
> 
>> After discussing the fact that we need to allow making all interactive
>> elements
>> visible, I realized perhaps this should be done through CSS.
> 
> 
> Yes, that's a good way to go.
>  
> 
>> Do we need a new CSS pseudoelement, such as :interactive?
> 
> 
> Can you explain its function? 
> 
>> Also, would people want to be able to make items with mouseovers look
>> different
>> from, say, items with onkeystroke events?
>> If so, how would that be done in CSS?
> 
> 
> CSS2 attribute selectors [1]:
> 
>    A[onmouseover] { background: yellow; color: black }
> 
>  _ Ian
> 
> [1] http://www.w3.org/TR/CSS2/selector.html#q10
> 

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