- From: Story Henry <henry.story@bblfish.net>
- Date: Tue, 1 Jul 2008 15:50:07 +0200
- To: <tim.glover@bt.com>
- Cc: <mgawinecki@gmail.com>, <semantic-web@w3.org>
- Message-Id: <04728866-160D-4F07-BA0D-0DDA5F1CB3BF@bblfish.net>
Yes views are very interesting. Simon Schenk has developed a Sail for Sesame that uses SPARQL construct queries to create views. I wrote up here: http://blogs.sun.com/bblfish/entry/opening_sesame_with_networked_graphs There is no need to remove namespaces for this to work btw. This is very very useful. Henry On 1 Jul 2008, at 15:33, <tim.glover@bt.com> wrote: > > > I think it is also interesting to make a comparison with SQL and > RDBMS, > which sets a pretty high bar for query languages. > > One of the great strengths of SQL/RDBMS is *views*. These shield users > (SQL queries) from changes in the underlying schema. I think this > would > have a particular application and relevance in the XML/RDF world, > because views could shield users from the complexity and > immovability of > namespaces. IMO there is a strong case for storing XML/RDF data with > no > namespaces, and add namespace information in views. > > I expect this has already been thought of - are there any > implementations out there? > > Tim. > > > > > -----Original Message----- > From: semantic-web-request@w3.org [mailto:semantic-web-request@w3.org] > On Behalf Of Maciej Gawinecki > Sent: 01 July 2008 11:21 > To: semantic-web@w3.org > Subject: comparing XML and RDF data models > > > In one of the article comparing two data models: XML and RDF I found a > statement stating that (I'm loosely citing from my memory): > > Searching XML with XPath query expression is easy if you know the > schema of the document being quiried. However, the same query will > not > work any a document, which is differently structured, but contains > equivalent information. This can be solved by usage of RDF model, > which can be then queried with RDQL or SPARQL query. > > Is that really true, that XPath-based XML search is limited due to its > structure? Yes, that's why there is a great research on keyword-based > quering of XML documents (not knowing schema in advance). But is it > RDF > really better for this issue ? > > I will try to give a few example what I exactly mean. [Of course, I'm > ommiting here the problem of knowning the name a tag/property/ > resource, > only the structure can be different.] Let's see two XML documents: > > <Sensor> > <name>Sensor220</name> > <isLocatedNearBy> > <Road> > E330 > </Road> > <isLocatedNearBy> > </Sensor> > > Here road value can be check through XPath expression: > \\Sensor\isLocatedNearBy\Road > > And let's see differently structured document (road defined by name > property) > > <Sensor> > <name>Sensor220</name> > <isLocatedNearBy> > <Road> > <name>E330</name> > </Road> > <isLocatedNearBy> > </Sensor> > > With XPath expression: \\Sensor\isLocatedNearBy\Road\name > > Or yet another one (road is ancestor tag to the sensor tag, not the > oposite) > > <Road> > <name>E330</name> > <hasSensor> > <Sensor> > <name>Sensor 220</name> > </Sensor> > </hasSensor> > </Road> > > XPath: \\Road\name > > The same problem would be with RDF. Let see the first model > > :Sensor220 :isLocatedNearBy :Road_E330 . > > WHERE clause of SPARQL query would be then like a > > ?s :isLocatedNearBy :Road_E330 . > > For other version we define a road with a specific value of hasName > property: > > :Sensor220 :isLocatedNearBy :RoadXXX . > :RoadXXX :hasName "E330" . > > the SPARQL query part: > > ?s :isLocatedNearBy ?r . > ?r :hasName "E330" . > > or by analogy to the third XML representation (road "has" a sensor, > not > the opposite): > > :RoadXXX :hasName "E330" . > :RoadXXX :hasSensor :Sensor220 . > > the SPARQL query part: > > ?r :hasName "E330" . > ?r :hasSensor ?s . > > Can someone comment it ? > > Thanks, > Maciej > > > >
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Received on Tuesday, 1 July 2008 13:51:43 UTC