- From: Jonas Sicking <jonas@sicking.cc>
- Date: Fri, 2 Mar 2012 05:20:37 +0100
- To: Webapps WG <public-webapps@w3.org>
Hi All, What should we do for the following scenario: store = db.createObjectStore("store"); index = store.createIndex("index", "x", { multiEntry: true }); store.add({ x: ["a", "b", {}, "c"] }, 1); index.count().onsuccess = function(event) { alert(event.target.result); } It's clear that the add should be successful since indexes never add constraints other than through the explicit 'unique' option. But what is stored in the index? I.e. what should a multiEntry index do if one of the items in the array is not a valid key? Note that this is different from if we had not had a multiEntry index since in that case the whole array is used as a key and it would clearly not constitute a valid key. Thus if it was not a multiEntry index 0 entries would be added to the index. But for multiEntry indexes we can clearly choose to either reject the entry completely and not store anything in the index if any of the elements in the array is not a valid key. Or we could simply skip any elements that aren't valid keys but insert the other ones. In other words, 0 or 3 would be possible valid answers to what is alerted by the script above. Currently in Firefox we alert 3. In other words we don't reject the whole array for multiEntry indexes, just the elements that are invalid keys. / Jonas
Received on Friday, 2 March 2012 04:21:34 UTC