Re: [PrototypeRoot]

Ian Hickson:
> I don't really mind exactly what the solution is; my only concern here 
> would be that I'd be throwing [PrototypeRoot] around a lot.

Acknowledged.  If you can propose a way of defining this without needing
to use [PrototypeRoot] a lot, that’d help.

> (I assume with PrototypeRoot that the most-derived interface that
> inherits from such an interface is automatically promoted to being the
> [[Class]]?)

That’s right.

-- 
Cameron McCormack ≝ http://mcc.id.au/

Received on Saturday, 20 June 2009 07:04:19 UTC