Re: BNODE(string) and joins

Not 100% sure I understand the question,could you maybe provide a concrete example?
You are right , that implementations shall generate two different blank nodes on each bnode(s) call with the same string.
Once they are created, e.g. in a bind, further up in joins these should behave as any other bnodes. 
--
Dr. Axel Polleres	
url: http://www.polleres.net/  twitter: @AxelPolleres

> On 04.10.2018, at 23:39, Marcel Otto <marcelotto.de@googlemail.com> wrote:
> 
> Hi,
> 
> I'm implementing a SPARQL engine in Elixir ([1], [2]). Currently, I'm implementing the interpretation of group graph patterns and have the following question an the handling of blank nodes generated with `BNODE(string)`. When performing the merge of two solutions for a `join`, which of the two merged solutions should the merged solution be based on with respect to `BNODE(string)`? For example, let's say I have two sub groups using the `BNODE(string)` function to generate bnodes for the same string, which would result due to the locality of the `BNODE` function different bnodes. So, when the `BNODE` function is now called in the outer group above the two subgroups, again with the same string, what bnode should be returned? 
> 
> Kind regards,
> Marcel Otto
> 
> [1] https://github.com/marcelotto/sparql-ex
> [2] https://lists.w3.org/Archives/Public/public-lod/2018Sep/att-0035/00-part - announcement about the whole project on the public-lod mailing list