- From: <felix@sasakiatcf.com>
- Date: Thu, 23 Sep 2021 09:10:17 +0200
- To: "'Holger Knublauch'" <holger@topquadrant.com>, <public-shacl@w3.org>
- Message-ID: <2a1301d7b04a$104784f0$30d68ed0$@sasakiatcf.com>
That works well, thanks, Holger. A side note about editing processes and validation. Then I edit a property and the whole graph is validated, an error like "two instances of the property in one branch" is detected. Then I edit a property and only the node the property is attached to is validated, errors are only detected if the duplicate node is *above* the node I am editing. I guess this issue could be handled by adding another sh:property with sh:and : ex:BranchShape a sh:NodeShape ; sh:targetSubjectsOf ex:myProperty ; sh:and ( sh:property [ sh:path ( [ sh:oneOrMorePath skos:broader ] ex:myProperty ) ; sh:maxCount 0 ; ] sh:property [ sh:path ( sh:inversePath ex:myProperty [ sh:oneOrMorePath skos:broader ]) ; sh:maxCount 0 ; ] ). Is this correct? Regards Felix Von: Holger Knublauch <holger@topquadrant.com> Gesendet: Donnerstag, 23. September 2021 02:29 An: felix@sasakiatcf.com; public-shacl@w3.org Betreff: Re: AW: Constraints on a property in a SKOS hierarchy On 2021-09-22 10:00 pm, felix@sasakiatcf.com <mailto:felix@sasakiatcf.com> wrote: Thanks a lot for the example, Holger. I tried this out. Attached is 1. your shape testshape.ttl 2. a testfile that throws an error, as expected testdata-fails-as-exepected.ttl 3. a testfile that does not throw an error: testdata-does-not-fail.ttl . The difference between 2) and 3) is that 3) has the same value for the ex:myProperty property. Does this make a difference? Ah yes, that's a good point. Path expressions will eliminate duplicates, so it will pass the maxCount constraint for this corner case! If the hierarchy is acyclic, the following should work, doing a skos:broader+ instead of skos:broader*. It basically means "None of the parent concepts can have a value for ex:myProperty". ex:BranchShape a sh:NodeShape ; sh:targetSubjectsOf ex:myProperty ; sh:property [ sh:path ( [ sh:oneOrMorePath skos:broader ] ex:myProperty ) ; sh:maxCount 0 ; ] . (This is again untested, as a dry pen-and-paper exercise) Holger I am using the TopQuadrant implementation https://github.com/TopQuadrant/shacl/ Regards Felix Von: Holger Knublauch <mailto:holger@topquadrant.com> <holger@topquadrant.com> Gesendet: Mittwoch, 22. September 2021 02:14 An: public-shacl@w3.org <mailto:public-shacl@w3.org> Betreff: Re: Constraints on a property in a SKOS hierarchy On 2021-09-21 6:57 pm, felix@sasakiatcf.com <mailto:felix@sasakiatcf.com> wrote: Dear all, I would like to to the following: 1. Define a property "ex:myProperty" for a skos:Concept. 2. In a given SKOS taxonomy, the following constraint should be formulated: for the taxonomy, the property should appear zero or more times in one "branch" of the taxonomy. If you really mean zero or more times, then this wouldn't constrain anything. My understanding is you want to say zero or one time, i.e. that there can be at most one value per branch? 3. The following would be a valid SKOS RDF graph: example:animal a skos:Concept; ex:myProperty "some value". example:bird a skos:Concept; skos:broader example:animal. The following would be a non-valid SKOS RDF graph, since example:bird is connected to another concept (example:animal) that already has ex:myProperty: example:animal a skos:Concept; ex:myProperty "some value". example:bird a skos:Concept; skos:broader example:animal; ex:myProperty "some value". Given the above assumption, could this simply become a maxCount 1 on a path expression skos:broader* / ex:myProperty? Untested draft: ex:BranchShape a sh:NodeShape ; sh:targetSubjectsOf ex:myProperty ; sh:property [ sh:path ( [ sh:zeroOrMorePath skos:broader ] ex:myProperty ) ; sh:maxCount 1 ; ] . I guess instead of the sh:targetSubjectsOf you could also simply attach this to all skos:Concepts. Holger How would I formulate 2) in SHACL? Regards Felix
Received on Thursday, 23 September 2021 07:10:33 UTC