- From: Jos de Bruijn <debruijn@inf.unibz.it>
- Date: Sun, 03 Feb 2008 11:40:29 +0100
- To: Michael Kifer <kifer@cs.sunysb.edu>
- CC: RIF WG <public-rif-wg@w3.org>
- Message-ID: <47A59A1D.3070502@inf.unibz.it>
Michael,
You're right. The definitions don't work. If we would fix them, we end
up with your option (b).
So we're back where we started, with the two choices you described in [1].
Best, Jos
[1] http://lists.w3.org/Archives/Public/public-rif-wg/2007Dec/0099.html
Michael Kifer wrote:
> Jos,
> thanks for the proposal. I have serious doubts that it holds water.
> Please see below.
>
>> Dear all,
>>
>> In the telephone conference last Tuesday I mentioned that I had an idea
>> for dealing with errors in built-in predicates and functions by not
>> defining the semantics in case errors occur.
>>
>> My proposed solution is the following:
>>
>> For the purpose of this definition I assume that built-in predicates and
>> functions are written as ' Builtin ( ' Uniterm ' ) ', following the
>> proposal "syntactic representation of built-ins in RIF" at [1].
>>
>> The definition of basic semantic structures is extended as follows:
>> I(Builtin(f(t1 ... tn))=IFb(f)(I(t1),...,I(tn))
>> ITruth(Builtin(r ( t1 ... tn ))) = IRb(r)(I(t1),...,I(tn))
>>
>> This is merely a routine extension of the interpretation of terms and
>> atomic formulas to that of built-in terms and atomic formulas. Note that
>> we use the mappings IFb and IRb for the interpretation of built-in
>> functions and predicates; it would have also been possible to extend the
>> current interpretation functions, but in this case are both that
>> introducing new mappings which make things clearer.
>>
>> Now for the interpretation of built-in functions and predicates:
>>
>> IFb is a mapping from Const to partial functions from D* into D
>>
>> IRb is a mapping from Const to partial truth-valued mappings D* TV
>>
>> Note that the difference with the definitions of IF and IR is that the
>> functions and truth value mappings are *partial*.
>>
>> A consequence of the fact that these mappings are partial is that the
>> truth valuation function ITruth may become undefined in case any errors
>> in built-in functions or predicates occur.
>>
>>
>> Let's now consider satisfaction of rules, which is defined as follows
>> (from the document):
>>
>> I |= then :- if
>>
>> iff ITruth(then) =t ITruth(if).
>>
>> If ITruth(then) or ITruth(if) is undefined, ITruth(then) =t ITruth(if)
>> will also be undefined. Therefore, I |= then :- if is undefined. This
>> extends to satisfaction of rule sets I |= R.
>
> Let the rule set be
>
> p(1).
> q(abc).
>
> r(?Y) :- add(1,?X,?Y), p(?X).
>
> You did not say how things work with universal quantifiers, but the
> definition certainly will look weird a bit. Moreover, universal
> quantification should be treated as (a possibly) infinite conjunction
> so if one extends your definition in the logical way then the above will
> have no models.
>
>> Now consider an entailment, which is defined as follows:
>>
>> S |= f
>>
>> iff for every semantic structure I, such that I |= S, it is the case
>> that Itruth(f)=t.
>>
>> If there is an error in the rule set S, then I |= S is undefined, so
>> clearly S |= f is undefined. If there is an error in f, then clearly
>> ITruth(f) is undefined, so S |= f is undefined.
>
> No, from what you said it follows that it is not the case that (S |= f).
>
>> So, the model theory simply does not interpret rule sets or conditions
>> with errors in built-ins.
>>
>> We should probably include a remark saying that implementations should
>> return an error whenever they encounter a rule set which is not interpreted.
>
> You should probably check that all the theories of minimal, WF, and stable
> models hold. You should also probably check if this holds water for the FOL
> case.
>
> I suspect that it does not because of the aforesaid universal
> quantification problem.
>
> This was just my 30-second reaction. Here is my 45-sec reaction.
>
> Say, "a" is true, "b" false, and "c" is undefined. What's the values of
>
> Itruth (a \/ c) = ?
> Itruth (b /\ c) = ?
>
> If it's true/false, then this is exactly the same as adding the undefined
> truth value and a 3-valued logic. We discussed this before.
>
> If it is undefined, then this is unacceptable, because it would mean that
> the following ruleset would have no models:
>
> q :- (p, a) \/ (r, c).
> p.
>
>
>
>
> --michael
>
>
>> Best, Jos
>>
>> [1] http://www.w3.org/2005/rules/wg/wiki/List_of_BLD_built-ins
>> --
>> Jos de Bruijn debruijn@inf.unibz.it
>> +390471016224 http://www.debruijn.net/
>> ----------------------------------------------
>> Doubt is not a pleasant condition, but
>> certainty is absurd.
>> - Voltaire
>
--
debruijn@inf.unibz.it
Jos de Bruijn, http://www.debruijn.net/
----------------------------------------------
One man that has a mind and knows it can
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-- George Bernard Shaw
Received on Sunday, 3 February 2008 10:41:03 UTC