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Q: The length of a rectangle is 3 inches less than twice the width If the perimeter of the rectangle is 18 inches what is the width of the rectangle?

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Length of rectangle is 5 inches and its width is 4 inches Check: 2*(5+4) = 18 inches which is its perimeter

A rectangle has two dimensions, length and width. You haven't said what the width is. The perimeter is the distance around the rectangle. Imagine going round it. You would go 42 inches, then a width, then another 42 inches, then another width. In general, the perimeter of a rectangle is twice its length plus twice its width.

If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.

The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.

The perimeter of a rectangle is 42. Meters. The length of the rectangle is threemeter less than twice the width.Mar

Do-it-in-your-head method: Length + width is half the perimeter which is 27 inches; 27 minus 6 is 21 and one-third of 21 is 7 which is the width. (Length = 2 x 7 + 6 = 20)

If you increase the rectangle's length by a value, its perimeter increases by twice that value. If you increase the rectangle's width by a value, its perimeter increases by twice that value. (A rectangle is defined by its length and width, and opposite sides of a rectangle are the same length. The lines always meet at their endpoints at 90° angles.)

Area is length times width, perimeter is twice the sum of length and breadth.

The perimeter of any rectangle is twice the sum of the length and the width of the rectangle; in the present instance, 2(n + 2n) = 6n.

Perimeter of a rectangle = twice (length + width), in this case 22 m.

Length = (Perimeter - twice width) / 2

156 It is impossible to calculate the area of a rectangle from its perimeter if no other dimension is known. The area of a rectangle is the product of its length and width, and the perimeter is twice the sum of its length and width.

Assuming it is rectangle, then the perimeter equal twice the summation of length and width. Answer = 2 x (14 + 24) = 2 x 38 = 76 inches

12 meters

If the width is 9' and the length is twice that, the length is 18'; the perimeter is twice the length plus twice the width, which is 36' + 18' = 54 feet.

The perimeter of a rectangle is twice the sum of the width and length: perimeter = 2 x (4.6in + 12.1 in) = 33.4 in

20 cm

2 (x + 2x) = 42 x + 2x = 21 3x = 21 Therefore, x = 7 The width of the rectangle is 7 inches. The length of the rectangle is 14 inches.

The length is 14 cm

Let L be the length of the rectangle and W the width, then L = 2W - 3. The perimeter = 2L + 2W = 2(2W - 3) + 2W = 6W - 6 But the perimeter measures 18"so, 6W - 6 = 18 : 6W = 24 : W = 4 The width of the rectangle is 4".

98 square feet

2x4

The length is 20 units and the width is 10 units

yes, because in finding perimeter youre just adding all of the sides together.

The dimensions of the rectangle are 21 units by 9 units