- From: Sandro Hawke <sandro@w3.org>
- Date: Thu, 08 Sep 2011 08:13:08 -0400
- To: Richard Cyganiak <richard@cyganiak.de>
- Cc: Pat Hayes <phayes@ihmc.us>, RDF Working Group WG <public-rdf-wg@w3.org>, Ivan Herman <ivan@w3.org>
On Thu, 2011-09-08 at 10:12 +0200, Richard Cyganiak wrote:
> On 7 Sep 2011, at 19:34, Sandro Hawke wrote:
> > I argued in todays meeting, off the cuff, that option 2 (in Pat's
> > email [1]) offers only aesthetic improvements, while options 3 and 4
> > will result in simpler code.
>
> Please provide some example code for:
>
> Option 3:
>
> - checking whether a literal is a string
LANG = "http://www.w3.org/ns/lang/"
XS = "http://www.w3.org/2001/XMLSchema"
def is_string(node):
return is_literal(node) and (
node.datatype == XS+"string" or
node.datatype.startswith(LANG) )
> - returning the language tag of a language-tagged string
def lang_tag(node):
assert node.datatype.startswith(LANG)
return node[len(LANG):]
> Option 4:
>
> - returning the lexical form of a literal
node.lexrep
I agree this is a significant compatibility problem, since it will
return chat@fr.
-- Sandro
> Thanks,
> Richard
>
Received on Thursday, 8 September 2011 12:13:21 UTC