Error in STRAFTER() example?

Spotted by the engineering team here.

http://www.w3.org/TR/2012/WD-sparql11-query-20120724/#func-strafter

This example seems to be wrong:
strafter("abc"^^xsd:string,"")	""^^xsd:string
I believe it should be 
strafter("abc"^^xsd:string,"")	"abc"^^xsd:string

The fn:substring-after says "If the value of $arg2 is the zero-length string, then the function returns the value of $arg1."

- Steve

-- 
Steve Harris, CTO
Garlik, a part of Experian
+44 7854 417 874  http://www.garlik.com/
Registered in England and Wales 653331 VAT # 887 1335 93
80 Victoria Street, London, SW1E 5JL

Received on Monday, 5 November 2012 12:34:39 UTC