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[Bug 28729] New: map:remove when multiple entries have the "same key" as $key

From: <bugzilla@jessica.w3.org>
Date: Mon, 01 Jun 2015 17:34:09 +0000
To: public-qt-comments@w3.org
Message-ID: <bug-28729-523@http.www.w3.org/Bugs/Public/>

            Bug ID: 28729
           Summary: map:remove when multiple entries have the "same key"
                    as $key
           Product: XPath / XQuery / XSLT
           Version: Candidate Recommendation
          Hardware: PC
                OS: All
            Status: NEW
          Severity: normal
          Priority: P2
         Component: XQuery 3.1
          Assignee: jonathan.robie@gmail.com
          Reporter: josh.spiegel@oracle.com
        QA Contact: public-qt-comments@w3.org
             Group: XSLXQuery_WG

>From the definition of map:remove:

"Returns a map containing all the entries from a supplied map, except for one."


"The function map:remove returns a ·map· containing all the entries in $map
except for any entry whose key is the ·same key· as $key."

These statements contradict each other in the case where $key is the "same key"
as multiple entries in the map.  For example:

  let $m := map { 
       xs:decimal("1.00000000000000000000000000000000001") : (),
       xs:decimal("1.00000000000000000000000000000000002") : ()
    map:remove($m, xs:double("1.0"))

The double value is equal to both decimal values.  Is one entry removed or

Note, map:get clarifies what happens in this situation:

"Where values of different numeric types are numerically very close to each
other, it can happen that the map contains two entries whose keys both match
the supplied key, but which are not equal to each other. In this situation the
entry that is returned is ·implementation-dependent·"

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Received on Monday, 1 June 2015 17:34:19 UTC

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