RE: (ESED-813) XOR operator in XPath

I should stress that my opinion isn't the last word on the matter. Unless
you want to withdraw the suggestion, it will be considered by the working
group as a whole.
 
Regards,

Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay 


  _____  

From: McDOWALL, Brent [mailto:Brent.McDOWALL@suncorp.com.au] 
Sent: 22 April 2010 06:31
To: 'Michael Kay'; 'public-qt-comments@w3.org'
Cc: EasySuite Operations
Subject: RE: (ESED-813) XOR operator in XPath



Hi Michael,

 

That wasn't really the response I was after, but thank you for the
suggestion and taking the time to look at the matter.

 

Regards,

 


easysuite_logo_small_just_text.png

BRENT MCDOWALL  |  System Analyst

EasySuite | Shared Services | BT Corporate Systems

Suncorp | Level 19 Suncorp Plaza | cnr Turbot & Albert Street, Brisbane 4000

ext: 21307 | tel: (07) 3362 1307 | fax: (07) 3362 2966 | ipc: IT042

 

 

From: Michael Kay [mailto:mike@saxonica.com] 
Sent: Wednesday, 21 April 2010 16:47
To: McDOWALL, Brent; public-qt-comments@w3.org
Cc: EasySuite Operations
Subject: RE: (ESED-813) XOR operator in XPath

 

 

However, for a user of XPath, I think providing the operator that directly
translates to the concept a user might be looking for, rather than a
'logically equivalent' operator, is a nice thing to do. It seems a simple
enough translation, but if I can spare my business users of XPath from
needing to make one more small leap in their boolean algebra cogitations,
then I'd be happy to do so. 

 

 

Well, you can always wrap it in a function  

 

declare function f:xor($a as xs:boolean, $b as xs:boolean)  as xs:boolean {

    $a != $b

}

 

Regards,

Michael Kay
http://www.saxonica.com/
http://twitter.com/michaelhkay 


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